[Haskell-cafe] Re: monad subexpressions

[Mirko Rahn]

>>> rewrite *p++=*q++ in haskell?

>> *p = *(p+1) ; *q = *(q+1)

> If that's true then GCC has gone insane, because they are completely different.

Of course you are  right, I just observed at the wrong place..., sorry 
for that.

> Though, as any C programmer knows, you really should be using
> memcpy()

I like to hear that you would reject it either.

/BR

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