[Haskell-cafe] Re: monad subexpressions
rahn at ira.uka.de
Fri Aug 3 07:47:47 EDT 2007
>>> rewrite *p++=*q++ in haskell?
>> *p = *(p+1) ; *q = *(q+1)
> If that's true then GCC has gone insane, because they are completely different.
Of course you are right, I just observed at the wrong place..., sorry
> Though, as any C programmer knows, you really should be using
I like to hear that you would reject it either.
-- Mirko Rahn -- Tel +49-721 608 7504 --
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