[Haskell-cafe] Weaving fun
Bas van Dijk
v.dijk.bas at gmail.com
Fri Apr 13 06:10:28 EDT 2007
On 4/11/07, Chris Kuklewicz <haskell at list.mightyreason.com> wrote:
> ...
> My previous weave, uses composition of (xs:) thunks instead of pairs:
>
> > weave :: [[a]] -> [a]
> > weave [] = []
> > weave xss = helper id xss
> > where helper :: ([[a]] -> [[a]]) -> [[a]] -> [a]
> > helper _rest ([]:_xss) = [] -- done
> > helper rest [] = weave (rest [])
> > helper rest ((x:xs):xss) = x : helper (rest . (xs:)) xss
>
> One might imagine an 'optimized' case like in weave':
>
> > -- helper rest ((x:[]):xss) = let yss = rest ([]:[])
> > -- in x : helper (const yss) xss
> ...
Nice! The iteration over the list can be abstracted using foldr:
> weave :: [[a]] -> [a]
> weave [] = []
> weave xss = foldr f (\rest -> weave $ rest []) xss id
> where
> f [] _ = \_ -> []
> f (x:xs) g = \rest -> x : g (rest . (xs:))
This is beginning to look scary :-) To enable your last optimization
you can replace the last alternative of 'f' by:
> f (x:xs) g = \rest -> x : g (\l -> rest $ case xs of
> [] -> [[]]
> xs -> xs:l
> )
The funny thing is that this definition looks very similar to my first
weave. However the reverse parts are now removed because of the
difference list trick:
> weave :: [[a]] -> [a]
> weave ll = work ll [] []
> where
> work ll = foldr f (\rst acc -> work (reverse rst) [] acc) ll
> f [] g = \_ acc -> reverse acc
> f (x:xs) g = \rst acc -> g (xs:rst) (x:acc)
Thanks,
Bas van Dijk
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