[Haskell-cafe] Expressing seq

Chad Scherrer chad.scherrer at gmail.com
Wed Sep 27 18:04:16 EDT 2006

> >
> > There must be a subtlety I'm missing, right?
> What if the types are not instances of Eq?
> Jason

Thanks, I figured it was something simple. Now I just to convince
myself there's no way around that. Is there a proof around somewhere?

Chad Scherrer

"Time flies like an arrow; fruit flies like a banana" -- Groucho Marx

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