[Haskell-cafe] Re: Trying to understand HList / hSequence now [why
it works]
oleg at pobox.com
oleg at pobox.com
Tue Oct 10 22:45:28 EDT 2006
Matthias Fischmann wrote:
> instance (Monad m, HSequence m HNil HNil) => HSequence m HNil HNil
> where hSequence _ = return HNil
>
> how can i use the goal of the declaration as one of the conditions
> without causing some sort of black hole in the type inference
> algorithm?
Very easily: the instance head is implicitly the part of its own
context (so that a method can be recursive). A simple way to see that
is the following deliberately erroneous class:
> class C a where mc :: a -> Bool
> instance Eq a => C a where mc x = x > x
The error message says
Could not deduce (Ord a) from the context (C a, Eq a)
arising from use of `>' at /tmp/f2.hs:30:36
It is revealing to observe the context that the typechecker thinks is
available: it is (C a, Eq a). "Eq a" is there because we explicitly
wrote it in the instance declaration. C a is there just by default. We
could just as well written
> instance (Ord a, C a) => C a where mc x = x > x
Incidentally, the hSequence can be written as follows
> import TypeCastGeneric2
> data ConsM
>
> instance (TypeCast (m1 l) (m l), Monad m)
> => Apply ConsM (m a, m1 l) (m (HCons a l)) where
> apply _ (me,ml) = liftM2 HCons me (typeCast ml)
>
> hSequence l = hFoldr (undefined::ConsM) (return HNil) l
> hlist = HCons (Just 1) (HCons (Just 'c') HNil)
> hlist2 = HCons ([1]) (HCons (['c']) HNil)
> testHSequence = hSequence hlist
> testHSequence2 = hSequence hlist2
*Foo> :t testHSequence
testHSequence :: Maybe (HCons Integer (HCons Char HNil))
*Foo> testHSequence
Just (HCons 1 (HCons 'c' HNil))
*Foo> testHSequence2
[HCons 1 (HCons 'c' HNil)]
The typechecker will complain if we try to mix different monads within
the same HList, and then sequence it.
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