[Haskell-cafe] why are implicit types different?

[S. Alexander Jacobson]

Why do g and g' have different types?

   g x y = let ?f = \x-> x in ?f x ++ (show (?f y))

   g' x y = let f = \x-> x in f x ++ (show (f y))

Is there a way I can use implicit types and let g be as general as g'?

-Alex-


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S. Alexander Jacobson tel:917-770-6565 http://alexjacobson.com