[Haskell-cafe] Haskell Quiz Solution - Haskell Newbie Requesting Review

Justin Bailey jgbailey at gmail.com
Fri Nov 10 13:39:47 EST 2006

On 11/10/06, Dougal Stanton <ithika at gmail.com> wrote:

> As you noted that doesn't seem right --- how does compile capture its
> input? Well, the (.) operator is slightly different. It captures
> variables and passes them into the 'innermost' function, a bit like
> this:

That is a great explanation. I've got a much better understanding of
the operator now - thanks very much!


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