[Haskell-cafe] Define combination of type classes?
Gerrit van den Geest
g.vandengeest at students.uu.nl
Fri Mar 24 03:09:58 EST 2006
Another option is to just add the instance:
> instance FooBar Char
instead of
> instance (Foo a, Bar a) => FooBar a
Now you don't need any extensions, the disadvantage is that you have to
add an instance for each type...
There has also been an proposal for type class synonyms:
http://repetae.net/john/recent/out/classalias.html
Maybe you like it,
Gerrit
Sean Seefried wrote:
>
> On 24/03/2006, at 12:45 PM, Fritz Ruehr wrote:
>
>> What is the easiest way to name a combination of type classes, i.e.,
>> to abbreviate the fact that a certain type is an instance of several
>> classes simultaneously? I have a vague sense that this is do-able,
>> but that I am messing up by trying to use an empty class body as below.
>>
>> So in the code below, I try to use FooBar to abbreviate the
>> conjunction of Foo and Bar. But while f (which uses a FooBar
>> constraint) has a valid definition, it can't be used. On the other
>> hand, g (which uses the long-winded constraint), is both a valid
>> defined and useable.
>>
>> (In a real example, imagine that FooBar names a conjunction of a
>> half dozen things, so that the g-like form really is onerous,
>> whereas the f-like form would be sweet and tidy :) .)
>>
>
> Hi Fritz!
>
> You only need to do a couple of things to get this working. Add an
> instance declaration:
>
> instance (Foo a, Bar a) => FooBar a
>
> But for this to work you need to allow undecidable instances (and -
> fglasgow-exts).
>
> To have this type class synonym trick work you need both the class
> and instance declaration:
>
> class (Foo a, Bar a) => FooBar a
> instance (Foo a, Bar a) => FooBar a
>
> The first ensures that members of class FooBar will inherit the
> methods of classes Foo and Bar. The second ensures that if there is a
> Foo and a Bar instance then there will be a FooBar instance. You were
> lacking this in your code hence the error message:
>
> > f 'a'
>
> No instance for (FooBar Char)
> arising from use of `f' at <interactive>:1:0
> Probable fix: add an instance declaration for (FooBar Char)
> In the definition of `it': it = f 'a'
>
> This is a neat trick. I've also used it to reduce onerous contexts.
>
> Sean
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