[Haskell-cafe] Fibonacci numbers generator in Haskell
Doug Quale
quale1 at charter.net
Fri Jun 16 10:01:21 EDT 2006
Mathew Mills <mathewmills at mac.com> writes:
> Is there anything that can be done (easily) to reduce the rounding errors?
The hint that I gave before is one easy way.
> fib :: Integer -> Integer
> fib x = let phi = ( 1 + sqrt 5 ) / 2
> in truncate( ( 1 / sqrt 5 ) * ( phi ^ x + 0.5) )
You run out of precision eventually. IEEE Double's give you about 15
decimal digits, so the results become approximate for x > 75.
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