[Haskell-cafe] Fibonacci numbers generator in Haskell

[Vladimir Portnykh]

Fibonacci numbers implementations in Haskell one of the classical examples. 
An example I found is the following:

fibs :: [Int]
fibs = 0 : 1 : [ a + b | (a, b) <- zip fibs (tail fibs)]

To get the k-th number you do the following:
Result = fibs !! k

It is elegant but creates a list of all Fibonacci numbers less than k-th, 
and the code is not very readable :).

I wrote my own Fibonacci numbers generator:

fib :: Int -> [Int]
fib 0 = [0,0]
fib 1 = [1,0]
fib n = [sum prevFib, head prevFib] where a = fib (n - 1)

To get the k-th number you do the following:

result = head (fib k)

It does not generate full list of Fibonacci numbers, but keeps only 2 
previous numbers, and has only one recursive call.
Because the list always has only 2 elements using the functions head and sum 
is a bit overkill.

Can we do better?

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