[Haskell-cafe] constant functions
David House
dmhouse at gmail.com
Fri Dec 29 16:37:14 EST 2006
On 29/12/06, ajb at spamcop.net <ajb at spamcop.net> wrote:
> And if you don't want to think about it, this should make everything
> clear:
My additions displayed below:
f :: A -> B -> C -> D
> f :: A -> (B -> (C -> D))
By right-associativity of f.
> f a :: B -> (C -> D)
> (f a) b :: C -> D
> ((f a) b) c :: d
s/d/D/
--
-David House, dmhouse at gmail.com
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