[Haskell-cafe] Re: iterative algorithms: how to do it in Haskell?

[Henk-Jan van Tuyl]

On Sat, 19 Aug 2006 10:28:33 +0200, Gene A <yumagene at gmail.com> wrote:

> *Iteration> fromtoby 1 12 2 (flip (^) 3)  -- cubing of the base list  
> above..

An easier way to write this:
fromtoby 1 12 2 (^3)

[...]
> *Iteration> fromtoby 12 42 3  (flip (**) 0.3333333333)

fromtoby 12 42 3  (**0.3333333333)

>
> Greetings from the Yuma Desert,
> gene
> _______________________________________________

Greetings from Holland,
Henk-Jan van Tuyl

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