[Haskell-cafe] Help using QuickCheck

[Udo Stenzel]

Benjamin Franksen wrote:
> I am asking help with using QuickCheck. I tried everything I could think 
> of, but invariably as soon as I start invoking the quickCheck function 
> on my property it fails with
> 
>     No instances for (Arbitrary (OrdSeq Int), Show (OrdSeq Int))

You need to define an `instance Arbitrary (OrdSeq Int)' for QuickCheck
to be able to generate test data.  `instance Show (OrdSeq Int)' is
needed so the offending example can be reported to you in case some test
fails.  You should believe your compiler when it tells you

>       add an instance declaration for (Arbitrary (OrdSeq Int), Show 
> (OrdSeq Int))

;-)

> "No instance for (Show (IO ()))..."

I think, this is an artefact of unresolved overloading or missing
instances.  Somehow GHCi attaches an unnecessary implicit `print'.  When
I played with QuickCheck, this error went away as soon as the rest of
the expression type checked.


Udo.
-- 
Life is Hard, But Life is Harder When You're Dumb.
	-- The Austin Lounge Lizards
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