[Haskell-cafe] Question on "case x of g" when g is a function

[Hamilton Richards]

If he really wanted to use a case-expression, he could write it this way:

>  f x = case x of
>         False -> 0
>         True  -> 1

--Ham

At 1:02 PM +0100 2005/1/27, Henning Thielemann wrote:
>On Thu, 27 Jan 2005 yeoh at cs.wisc.edu wrote:
>
>>  Can a kind soul please enlighten me on why f bit0 and f bit1
>>  both return 0?
>>
>>  > bit0     = False
>>  > bit1     = True
>>  > f x = case x of
>>  >         bit0 -> 0
>>  >         bit1 -> 1
>
>If you compile with 'ghc -Wall' GHC should report that the identifier
>'bit0' in the case expression shadows the global 'bit0' identifier. What
>you want to do is:
>
>f x = if x == bit0 then 0 else 1
>
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