[Haskell-cafe] Re: what is inverse of mzero and return?
Jorge Adriano Aires
jadrian at mat.uc.pt
Sun Jan 23 15:31:23 EST 2005
> Am Sonntag, 23. Januar 2005 15:58 schrieb Jorge Adriano Aires:
> > I'm not arguing that definition would be "wrong". It is a monoid. This is
> > the instance for ():
> > instance MonadPlus() where
> > mzero = ()
> > mplus a b = ()
> Maybe I'm stupid, but:
> class Monad m => MonadPlus m where
> mzero :: m a
> mplus :: m a -> m a -> m a
> How does () fit into this, () isn't of kind * -> *, as far as I know
> () Int is meaningless -- just checked, gives Kind Error.
Nope, I am. Sorry! I was alternating between monoids and monadplus, and came
up with that nonsense. I was obviously thinking about Monoid () and not
> > And this would be "correct" too:
> > instance MonadPlus Maybe where
> > mzero = Nothing
> > mplus a b = Nothing
> >> instance MonadPlus  where
> > mzero = 
> > mplus a b = 
> Both aren't correct, since mzero `mplus` x == x
> doesn't hold (they're syntactically correct, though).
Yeap. You are right again. Sorry for this terrible example, please ignore it.
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