[Haskell-cafe] Dividing integers?
Ferenc Wagner
wferi at afavant.elte.hu
Thu Mar 18 15:08:41 EST 2004
"Matias Hernandez" <matiash at artech.com.uy> writes:
> I mean, apparently "/" is not defined for integers but I
> don't know how to "cast" the result of the length function
> into a Double...
>
> Prelude> (length [1,2]) / 3
Prelude> fromIntegral (length [1,2])/3
0.666666666666667
> Prelude> 2 / 3
> 0.6666666666666666
Literal 2 means fromIntegral 2, but length::[a]->Int.
--
Feri.
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