[Haskell-cafe] Why no IO transformer monad?
Keean Schupke
k.schupke at imperial.ac.uk
Mon Dec 20 06:09:21 EST 2004
I thought you would get the following if you have a transformer 'M':
runM :: M IO a -> IO a
to run 'M'...
Keean.
Udo Stenzel wrote:
>Keean Schupke <k.schupke at imperial.ac.uk> schrieb am 20.12.04 10:25:36:
>
>
>>What about:
>>
>> runIOT :: Monad m => IOT m a -> IO (m a)
>>
>>
>
>I have a gut feeling that this is unimplementable. However, IO (m a) is
>what you get using the transformer version of m over IO.
>
>
>Udo.
>
>
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