[Haskell-cafe] Combination-lock problem
iakd0 at clusterf.urz.uni-halle.de
Wed Aug 11 13:01:18 EDT 2004
On Wed, 11 Aug 2004, Lyle Kopnicky wrote:
> Here's my version:
> combs  = 
> combs [n] = [[i] | i <- [0..n]]
> combs (n:r) = let combsr = combs r in [i:cr | i <- [0..n], cr <- combsr]
Since there is one zero combination, it should be
> combs  = []
Then you can also remove the definition of combs [n] .
What is the advantage of introducing 'combsr' instead of using 'combs r'
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