composeList
David Feuer
dfeuer@cs.brown.edu
Sun, 12 May 2002 23:57:27 -0400
See comments below.
On Sun, May 12, 2002, David Feuer wrote:
> On Sun, May 12, 2002, Emre Tezel wrote:
> > Hi all,
> >
> > I recently bought Simon Thompson's Haskell book. I have been doing the
> > exercises while I read on. There are couple questions that I can not
> > solve. Any help would be greatly appreciated.
> >
> > I got stuck on this question in Chapter 10.
> >
> > Define a function composeList which composes a list of functions into a
> > single function. What is the type of composeList?
> >
> > I naively tried the following but the hugs compiler complained about the
> > inferred type not being generic enough.
> >
> > composeList :: [(a -> b)] -> (c -> b)
> > composeList [] = id
> > composeList (x:xs) = x . (composeList xs)
<snip>
> You can do a lot better in Glasgow Haskell:
>
> data Fun a b = forall c . Comp (c -> b) (Fun a c) | End (a -> b)
>
> compose :: Fun a b -> a -> b --GHC needs this type signature
> --to compile the program, but
> --I don't understand why.
> --Any tips?
> compose (End f) = f
> compose (Comp f l) = f . compose l
Well, I figured out why the type signature is necessary (polymorphic
recursion), but I don't understand the error message I got from GHC:
cc.hs:5:
Inferred type is less polymorphic than expected
Quantified type variable `c' escapes
When checking a pattern that binds
f :: c -> b
l :: Fun a c
In the definition of `compose':
compose (Comp f l) = f . (compose l)
What makes it think that `c' escapes? This message had me staring at the code
the wrong way for quite a while before I decided to add a type signature and
see if that gave me any more useful information.
>
> f::Int -> Float
> f x = fromIntegral x
>
> g::String -> Int
> g = read
>
> h::Int -> String
> h x = take x "123456789"
>
> main = do
> putStrLn "hello!"
> print $ compose (End (\x -> "Foo!")) 3
> print $ compose (Comp f (Comp g (End h))) 4
--
Night. An owl flies o'er rooftops. The moon sheds its soft light upon
the trees.
David Feuer