(no subject)
xoo
ixoo21@hotmail.com
Wed, 5 Jun 2002 19:59:13 +0800
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hi.. i was just wondering if some body could give a simple equation for =
the following situation.other than recursion plz..
occurrences :: Eq a =3D> a -> [a] -> [a]
--occurrences xs ys returns the number of times that xs occurs in ys
thanks
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 5.50.4134.600" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>hi.. i was just wondering if some body =
could give a=20
simple equation for the following situation.other than recursion=20
plz..</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>occurrences :: Eq a =3D> a -> [a] =
->=20
[a]</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>--occurrences xs ys returns the number =
of times=20
that xs occurs in ys</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>thanks</FONT></DIV></BODY></HTML>
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