i can't see the solution

Sun, 25 Nov 2001 11:51:30 +0100

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it's an .lhs file

> data Alumno =3D A { dni :: Integer, nombre :: String,nota::Float }

> shf :: Alumno -> String
> shf alum  =3D show (dni alum) ++ nombre alum  ++ show (nota alum )

i don't wanna use this sentence:  deriving Show
i wanna use "my show function" but ...
Here is the problem !!

> instance Show a =3D> Show (Alumno  a) where
>      show x =3D shf x=20

Thanks .

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2600.0" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>it's an .lhs file</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>&gt; data Alumno =3D A { dni :: =
Integer, nombre ::=20
String,nota::Float }<BR>
<DIV><FONT face=3DArial size=3D2>&gt; shf :: Alumno -&gt; String<BR>&gt; =
shf=20
alum&nbsp; =3D show (dni alum) ++ nombre alum&nbsp; ++ show (nota alum=20
)</FONT></DIV></FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>i don't wanna use this sentence: =
&nbsp;deriving=20
Show</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>i wanna use "my show function" but =
...</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Here is the problem !!</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>&gt;&nbsp;instance Show a =3D&gt; Show =
(Alumno&nbsp;=20
a) where<BR>&gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; show x =3D shf x =
</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>Thanks .</FONT></DIV></BODY></HTML>

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