UNPACK Existential datatype

[Simon Peyton Jones]

I think this is a very reasonable suggestion.  It would take some work to implement, but nothing fundamental.

Simon

From: Glasgow-haskell-users [mailto:glasgow-haskell-users-bounces at haskell.org] On Behalf Of Nicholas Clarke
Sent: 20 January 2015 13:08
To: glasgow-haskell-users at haskell.org
Subject: Fwd: UNPACK Existential datatype

I'd like to be able to use the UNPACK pragma on an existentially quantified datatype. So as in the below example:

{-# LANGUAGE ExistentialQuantification #-}

data Foo = forall a. Show a => Foo !a
instance Show Foo where
  show (Foo a) = "Foo! " ++ show a

data Bar =
    Bar {-# UNPACK #-} !Foo
  deriving (Show)

main :: IO ()
main = do
  let foo = Foo "Hello"
      bar = Bar foo
  print bar

I would expect the `Foo` constructor to be unpacked into Bar, as if I had written:

data Bar = forall a. Show a => Bar !a

However, instead I get the 'Ignoring unusable UNPACK pragma on the first argument of ‘Bar’' warning. Is there a reason this shouldn't work, or a workaround to get it to do so?

Cheers,

Nick


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