Records in Haskell
strake888 at gmail.com
Sat Dec 31 00:39:24 CET 2011
Certainly not no conflicts: lambda expressions.
On 30/12/2011, Colin Adams <colinpauladams at gmail.com> wrote:
> On 30 December 2011 15:55, Matthew Farkas-Dyck <strake888 at gmail.com> wrote:
>> On 30/12/2011, Andriy Polischuk <quuxity at gmail.com> wrote:
>> > Yet another idea:
>> > Consider using '\' as record access operator. No conflicts with anything
>> > all, and,
>> > moreover, it really looks like hierarchical access. Reminds of
>> > though.
>> I hope this is a joke.
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