Bug in type equality constraints?

Simon Peyton-Jones simonpj at microsoft.com
Wed Jul 16 15:51:57 EDT 2008


That looks like a bug, at least on the surface.  You've clearly said that the instance for InnerSpace (u,v) can assume (Scalar u ~ Scalar v).

Can you spare a moment submit a Trac report, with a reproducible test case (as small as possible, please!)?

Manuel is actively working on associated types etc at the moment.  Our goal is a pretty-much-fully-working implementation for release in 6.10 just before ICFP.



From: glasgow-haskell-users-bounces at haskell.org [mailto:glasgow-haskell-users-bounces at haskell.org] On Behalf Of Conal Elliott
Sent: 15 July 2008 15:59
To: glasgow-haskell-users at haskell.org
Subject: Bug in type equality constraints?

I'm converting some code from functionally dependencies to associated types, and I've run into a problem with equality constraints and subclasses.  The classes:

    class AdditiveGroup v => VectorSpace v where
      type Scalar v :: *
      (*^) :: Scalar v -> v -> v

    class VectorSpace v => InnerSpace v where
      (<.>) :: v -> v -> Scalar v

Products of vector spaces are vector spaces *if* over the same scalar field.  Hence:

    instance ( VectorSpace u,VectorSpace v
             , Scalar u ~ Scalar v ) => VectorSpace (u,v) where
      type Scalar (u,v) = Scalar u
      s *^ (u,v) = (s*^u,s*^v)

Similarly for inner product spaces:

    instance ( InnerSpace u,InnerSpace v, Scalar u ~ Scalar v
         , AdditiveGroup (Scalar v) ) => InnerSpace (u,v) where
      (u,v) <.> (u',v') = (u <.> u') ^+^ (v <.> v')

But here's where ghc-6.9.20080622 balks:

    Couldn't match expected type `Scalar v'
           against inferred type `Scalar u'
    When checking the super-classes of an instance declaration
    In the instance declaration for `InnerSpace (u, v)'

Any ideas?

  - Conal
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