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PART A

11) Find the vertex of f(x) = -2x^2 - 8x + 3 algebraically.

My Answer: (-2,0)

12) Multiply and simplify: (6 - 5i) (4 + 3i)

My Answer: 39 - 2i

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- Thread starter
- #1

PART A

11) Find the vertex of f(x) = -2x^2 - 8x + 3 algebraically.

My Answer: (-2,0)

12) Multiply and simplify: (6 - 5i) (4 + 3i)

My Answer: 39 - 2i

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- #2

- Feb 14, 2012

- 3,941

I get $(-2, 11)$. Now can you help me by explaining to us how did you arrive at $(-2, 0)$ as the vertex of the function of f of x?Basically I don't know anyone in real life that can help me with this, so I need help checking to see if my answers are correct

PART A

11) Find the vertex of f(x) = -2x^2 - 8x + 3 algebraically.

My Answer: (-2,0)

Correct.12) Multiply and simplify: (6 - 5i) (4 + 3i)

My Answer: 39 - 2i

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- #3

- Admin
- #4

- Feb 14, 2012

- 3,941

Yes...and as you can see, $f(-2)=-2(-2)^2-8(-2)+3=11$.