Template Haskell...
MR K P SCHUPKE
k.schupke at imperial.ac.uk
Wed Oct 20 11:49:38 EDT 2004
Thanks for the URL... I have realised I jumped the gun saying the derivation can be
done in template-haskell... there is one small problem:
$(derive [t| SomeConstructor a b |])
passes the constructor to derive... is there any way to get the type information
for some type? You can do
$(derive [d| data X a b = X1 a b |])
Is there any way to get the same information from something like:
$(derive2 [T| X a b |])
Keean.
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