Why does sizeOf Word64 = 4?
Alastair Reid
alastair at reid-consulting-uk.ltd.uk
Sun Nov 9 08:51:11 EST 2003
> Hi, I'm trying to learn about Haskell's FFI (running 6.0.1 on linux)
> and see the following weird behavior with ghci:
You're seeing the right behaviour.
> Shouldn't "sizeOf nullPtr" return an error? And sizeOf a Ptr Word64
> should be 8 I think.
The size of a Word64 value is 8 but the size of a pointer is always the same
no matter what the pointer points to. Since most machines have 32-bit
addresses, the size of a pointer will be 4 on most machines.
A null pointer is just another machine address and has to be the same size as
any other machine address so, again, it has to be the same size.
> Also this program prints "4", when it seems it
> should print "8":
>
> module Main where
> import Data.Word
> import Foreign.Storable
> import Foreign.Ptr
> import Foreign.StablePtr
>
> x :: Word64
> x = 5
>
> main = do x_sptr <- newStablePtr 5
> putStrLn $ show $ sizeOf x_sptr
This is a stable pointer to an Int.
Again, the type and, in particular, the size of the thing pointed
to is irrelevant.
I can't be bothered looking it up but the size returned is either
the size of a machine address (void* in C) or the size of int in C.
Either way it is 4 on most machines.
It looks like you intended to create a stable pointer to x which is
a Word64. This would not have affected the result. Indeed, you
could have created a stable pointer to a complex Haskell data structure
like a binary tree or a function (i.e., something the FFI doesn't
directly support) and the size would still be the same because all you
are doing is passing a pointer to the object.
--
Alastair Reid www.haskell-consulting.com
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