HsParser does not allow method declarations to follow a default
implementation of a method.
class G a where
f :: a -> a
f x = x
g :: a -> a
Optional semicolons or empty statements are not permitted in
do-expressions.
f x = do ;; x ;
That is probably the reason why this example fails to parse too:
f x = do
y
where y = x
Anders Lau Olsen