[GHC] #16209: GHC behaves differently when binding has separate or inlined type declaration
GHC
ghc-devs at haskell.org
Mon Jan 21 16:50:41 UTC 2019
#16209: GHC behaves differently when binding has separate or inlined type
declaration
-------------------------------------+-------------------------------------
Reporter: fghibellini | Owner: (none)
Type: bug | Status: new
Priority: normal | Milestone:
Component: Compiler | Version: 7.10.3
Keywords: | Operating System: Unknown/Multiple
Architecture: | Type of failure: GHC rejects
Unknown/Multiple | valid program
Test Case: | Blocked By:
Blocking: | Related Tickets:
Differential Rev(s): | Wiki Page:
-------------------------------------+-------------------------------------
{{{#!hs
{-# LANGUAGE RankNTypes #-}
{-# LANGUAGE ScopedTypeVariables #-}
main = do
let a :: forall t. Functor t => t () = undefined
let g :: forall u. Functor u => u () = a
putStrLn "success"
}}}
fails with:
{{{
source_file.hs:6:44:
Couldn't match expected type ‘forall (u :: * -> *).
Functor u =>
u ()’
with actual type ‘t0 ()’
When checking that: t0 ()
is more polymorphic than: forall (u :: * -> *). Functor u => u ()
In the expression: a
}}}
but the following compiles successfully
{{{#!hs
{-# LANGUAGE RankNTypes #-}
{-# LANGUAGE ScopedTypeVariables #-}
main = do
let a :: forall t. Functor t => t () = undefined
let g :: forall u. Functor u => u ()
g = a
putStrLn "success"
}}}
On GHC 7.10 it works as described above. On newer ones it fails even on
the "functioning code".
{{{
a.hs:5:44: error:
• Cannot instantiate unification variable ‘a0’
with a type involving foralls:
forall (t :: * -> *). Functor t => t ()
GHC doesn't yet support impredicative polymorphism
• In the expression: undefined
In a pattern binding:
a :: forall (t :: * -> *). Functor t => t () = undefined
In the expression:
do let a :: forall t. Functor t => t () = undefined
let g :: forall u. Functor u => u ()
g = a
putStrLn "success"
}}}
--
Ticket URL: <http://ghc.haskell.org/trac/ghc/ticket/16209>
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