[GHC] #13358: Role ranges (allow decomposition on newtypes)
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ghc-devs at haskell.org
Wed Mar 1 08:33:39 UTC 2017
#13358: Role ranges (allow decomposition on newtypes)
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Reporter: ezyang | Owner: (none)
Type: feature request | Status: new
Priority: normal | Milestone:
Component: Compiler (Type | Version: 8.1
checker) |
Resolution: | Keywords: backpack
Operating System: Unknown/Multiple | Architecture:
| Unknown/Multiple
Type of failure: None/Unknown | Test Case:
Blocked By: | Blocking:
Related Tickets: | Differential Rev(s):
Wiki Page: |
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Description changed by ezyang:
Old description:
> Extracted from #13140.
>
> Today, there is a strange asymmetry between data types, for which the
> decomposition rule holds (if `T A ~R T B` then `A ~ρ B`, where ρ is the
> role of the type), and newtypes, for which the decomposition rule is
> unsound.
>
> I believe the root cause of this problem is the fact that we only
> maintain a single role per type parameter, while in fact what we need is
> a role *range* (i.e., and lower and upper role bound) to specify what
> inferences can be made about a type. Here's how it works.
>
> Every type parameter is ascribed a role range, specifying the possible
> roles by which the type parameter might possibly be used. For example, if
> I write `data T a = MkT a`, `a` is used exactly at representational role,
> but we could also say that a *might* be used nominally, giving the role
> range nominal-representational.
>
> The lower bound (nominal is lowest in subroling) specifies at what role
> the application rule is valid: if I say that the role is at least
> nominal, then I must provide `a ~N b` evidence to show that `T a ~R T b`.
> The upper bound (phantom is highest) specifies at what role the
> decomposition rule is valid. If I say that the role is at most phantom, I
> learn nothing from decomposition; but if I say the role is at most
> representational, when `T A ~R T B`, I learn `A ~R B`. Clearly, the role
> range nominal-phantom permits the most implementations, but gives the
> client the least information about equalities.
>
> How do we tell if a role range is compatible with a type? The lower bound
> (what we call a role today) is computed by propagating roles through, but
> allowing substitution of roles as per the subroling relationship `N <= R
> <= P`. To compute the upper bound, we do exactly the same rules, but with
> the opposite subroling relation: `P <= R <= N`.
>
> Some examples:
>
> {{{
> type app role T representational
> type proj role T representational
> newtype T a = MkT a
> -- T a ~R T b implies a ~R b
>
> type app role T nominal
> type proj role T representational
> -- NB: type proj role T nominal is NOT ALLOWED
> newtype T a = MkT a
> -- T a ~R T b implies a ~R b, BUT
> -- a ~R b is insufficient to prove T a ~R T b (you need a ~N b)
>
> type app role T nominal
> type proj role T phantom -- (representational and nominal not allowed)
> newtype T a = MkT Int
> -- T a ~R T b implies a ~P b (i.e. we don't learn anything)
> -- a ~N b implies T a ~R T b
> }}}
>
> Richard wonders if we could use this to solve the "recursive newtype
> unwrapping" problem. Unfortunately, because our solver is guess-free, we
> must also maintain the most precise role for every type constructor. See
> https://ghc.haskell.org/trac/ghc/ticket/13140#comment:12
New description:
Extracted from #13140.
Today, there is a strange asymmetry between data types, for which the
decomposition rule holds (if `T A ~R T B` then `A ~ρ B`, where ρ is the
role of the type), and newtypes, for which the decomposition rule is
unsound.
I believe the root cause of this problem is the fact that we only maintain
a single role per type parameter, while in fact what we need is a role
*range* (i.e., and lower and upper role bound) to specify what inferences
can be made about a type. Here's how it works.
Every type parameter is ascribed a role range, specifying the possible
roles by which the type parameter might possibly be used. For example, if
I write `data T a = MkT a`, `a` is used exactly at representational role,
but we could also say that a *might* be used nominally, giving the role
range nominal-representational.
The lower bound (nominal is lowest in subroling) specifies at what role
the application rule is valid: if I say that the role is at least nominal,
then I must provide `a ~N b` evidence to show that `T a ~R T b`. The upper
bound (phantom is highest) specifies at what role the decomposition rule
is valid. If I say that the role is at most phantom, I learn nothing from
decomposition; but if I say the role is at most representational, when `T
A ~R T B`, I learn `A ~R B`. Clearly, the role range nominal-phantom
permits the most implementations, but gives the client the least
information about equalities.
How do we tell if a role range is compatible with a type? The lower bound
(what we call a role today) is computed by propagating roles through, but
allowing substitution of roles as per the subroling relationship `N <= R
<= P`. To compute the upper bound, we do exactly the same rules, but with
the opposite subroling relation: `P <= R <= N`.
Some examples:
{{{
type role T representational..representational
newtype T a = MkT a
-- T a ~R T b implies a ~R b
type role T nominal..representational -- NB: nominal..nominal illegal!
newtype T a = MkT a
-- T a ~R T b implies a ~R b, BUT
-- a ~R b is insufficient to prove T a ~R T b (you need a ~N b)
type role T nominal..phantom -- NB: nominal..representational illegal!
newtype T a = MkT Int
-- T a ~R T b implies a ~P b (i.e. we don't learn anything)
-- a ~N b implies T a ~R T b
}}}
Richard wonders if we could use this to solve the "recursive newtype
unwrapping" problem. Unfortunately, because our solver is guess-free, we
must also maintain the most precise role for every type constructor. See
https://ghc.haskell.org/trac/ghc/ticket/13140#comment:12
--
--
Ticket URL: <http://ghc.haskell.org/trac/ghc/ticket/13358#comment:1>
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