[GHC] #12143: ApplicativeDo Fails to Desugar 'return True'
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Fri Jun 3 14:05:13 UTC 2016
#12143: ApplicativeDo Fails to Desugar 'return True'
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Reporter: MichaelBurge | Owner:
Type: bug | Status: new
Priority: normal | Milestone:
Component: Compiler | Version: 8.0.1
Resolution: | Keywords:
Operating System: Unknown/Multiple | Architecture:
| Unknown/Multiple
Type of failure: None/Unknown | Test Case:
Blocked By: | Blocking:
Related Tickets: | Differential Rev(s):
Wiki Page: |
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Description changed by MichaelBurge:
@@ -1,2 +1,1 @@
- If I bring in a spurious parameter, ApplicativeDo correctly infers Functor
- if I bind an unused variable:
+ ApplicativeDo correctly infers Functor if I bind an unused variable:
@@ -14,3 +13,2 @@
- I would expect the second example desugar to Functor or Applicative. And
- maybe 'return True' should be Monad, but 'do { return True; }' should be
- Applicative?
+ And maybe 'return True' should be Monad, but 'do { return True; }' should
+ be Applicative?
New description:
ApplicativeDo correctly infers Functor if I bind an unused variable:
{{{
Prelude> :t \m -> do { x <- m; return True; }
\m -> do { x <- m; return True; } :: Functor f => f t -> f Bool
Prelude> :t \m -> do { m; return True; }
\m -> do { m; return True; } :: Monad m => m a -> m Bool
}}}
It seems like if 'x' is unused, then 'x <- m' and 'm' should be
equivalent.
And maybe 'return True' should be Monad, but 'do { return True; }' should
be Applicative?
--
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Ticket URL: <http://ghc.haskell.org/trac/ghc/ticket/12143#comment:3>
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