Re: [GHC] #11553: `round (± ∞ :: Double)` not infinite
GHC
ghc-devs at haskell.org
Sun Feb 7 09:01:01 UTC 2016
#11553: `round (± ∞ :: Double)` not infinite
-------------------------------------+-------------------------------------
Reporter: hvr | Owner:
Type: bug | Status: new
Priority: normal | Milestone:
Component: libraries/base | Version:
Resolution: | Keywords:
Operating System: Unknown/Multiple | Architecture:
Type of failure: Incorrect result | Unknown/Multiple
at runtime | Test Case:
Blocked By: | Blocking:
Related Tickets: | Differential Rev(s):
Wiki Page: |
-------------------------------------+-------------------------------------
Description changed by hvr:
@@ -1,1 +1,1 @@
- Rounding 1/0 or 0/0 results in an arbitrary chosen `Integer` value, e.g.
+ Rounding 1/0 or -1/0 results in an arbitrary chosen `Integer` value, e.g.
@@ -9,0 +9,3 @@
+
+ λ:4> (round (0/0 :: Double) :: Integer) == -(2^1024 + 2^1023)
+ True
New description:
Rounding 1/0 or -1/0 results in an arbitrary chosen `Integer` value, e.g.
{{{
λ:2> (round (1/0 :: Double) :: Integer) == 2^1024
True
λ:3> (round (-1/0 :: Double) :: Integer) == -(2^1024)
True
λ:4> (round (0/0 :: Double) :: Integer) == -(2^1024 + 2^1023)
True
}}}
I'm not sure if this is more desirable than returning a bottom value (e.g.
by throwing some `ArithException`)
--
--
Ticket URL: <http://ghc.haskell.org/trac/ghc/ticket/11553#comment:1>
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