In C--: should CmmCall and CmmProc agree on their live registers?

Moritz Angermann moritz.angermann at gmail.com
Fri Oct 6 03:36:42 UTC 2017


Hi Simon,

no, I did not until now. Thank you! As such it is acceptable that the CmmCalls
set of live registers is a superset of the CmmProcs live registers that is called.

Say we shrink the set of live registers of the CmmProc, as we determine that some of the
arguments passed in registers are not used in the graph at all.  Would we want to
propagate this information to the CmmCall if possible?

Cheers,
 Moritz


> On Oct 5, 2017, at 5:59 PM, Simon Peyton Jones <simonpj at microsoft.com> wrote:
> 
> Did you ever get a reply to this?
> 
> In the output of the codegen, CmmProcs should have no live registers apart from those used to pass args, and the standard ones.
> 
> Simon
> 
> |  -----Original Message-----
> |  From: ghc-devs [mailto:ghc-devs-bounces at haskell.org] On Behalf Of Moritz
> |  Angermann
> |  Sent: 22 September 2017 07:33
> |  To: GHC developers <ghc-devs at haskell.org>
> |  Subject: In C--: should CmmCall and CmmProc agree on their live registers?
> |  
> |  Hi,
> |  
> |  apologies for writing so many emails recently. This is a minor spinoff from
> |  the "The Curious Case of T6084" email.
> |  
> |  While digging into it, I keep asking myself if CmmProc’s live registers
> |  should match those of the CmmCall that is calling it?
> |  
> |  Is there any invariant we try to enforce or would want to enforce?
> |  
> |  - Can the CmmProcs live registers be a strict superset of
> |    the corresponding CmmCalls?
> |  
> |    From the source comments in `compiler/cmm/Cmm.hs`:
> |    > Registers live on entry. Note that the set of live
> |    > registers will be correct in generated C-- code, but
> |    > not in hand-written C-- code. However,
> |    > splitAtProcPoints calculates correct liveness
> |    > information for CmmProcs.
> |  
> |    I would assume that this is an invalid case?
> |  
> |  - Can the CmmProcs live registers be a strict subset of
> |    the corresponding CmmCalls?
> |  
> |    This case however seems to be valid case.  However, this
> |    makes me wonder if we can, and should(?) propagate the
> |    live register info from the CmmProc to the CmmCall so
> |    that they match up, and the registers are not kept live
> |    at the origin of the CmmCall if they aren’t needed?  And
> |    as such potentially compute anything to put into the
> |    registers the CmmCall considers live, but the CmmProc
> |    would ignore anyway?
> |  
> |  Cheers,
> |   Moritz
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