DeriveFoldable treatment of tuples is surprising

Edward Kmett ekmett at gmail.com
Tue Mar 21 21:29:20 UTC 2017


As I recall, Richard Eisenberg has been pushing, off and on, for us to get
a better vocabulary to specify "how" something is derived, via
DeriveAnyClass, generalized newtype deriving, DeriveFoldable, etc.

In general I think the current behavior is the least surprising as it
"walks all the a's it can" and is the only definition compatible with
further extension with Traversable. Right now there are no instances
provided by base that violate the "walk all the a's" intuition and there is
a fair bit of user code for things like vector types that do things like

newtype V3 a = V3 (a,a,a,a)

replacing that with a data type isn't without cost because now converting
back and forth between that and a tuple could no longer be done for zero
cost with coercions. This style of code is more common among the
ML-turned-haskeller crowd, whom -- in my experience -- tend to think of it
as just giving the constructor paren around its arguments rather than as a
tuple.

Destroying Foldable for that and making working code not work just for
users to have to manually specify multiple tedious instances that should be
easily derivable shouldn't be a thing we do lightly. DeriveFunctor doesn't
consider that functors involved may be contravariant either. DeriveFoo
generally does something that is a best effort.

I'm more inclined to leave it on the list of things that DeriveFoo does
differently than GND, and as yet another argument pushing us to find a
better vocabulary for talking about deriving.

-Edward


On Tue, Mar 21, 2017 at 5:11 PM, David Feuer <david.feuer at gmail.com> wrote:

> The point is that there are two reasonable ways to do it, and the
> deriving mechanism, as a rule, does not make choices between
> reasonable alternatives.
>
> On Tue, Mar 21, 2017 at 5:05 PM, Jake McArthur <jake.mcarthur at gmail.com>
> wrote:
> > I think it's a question of what one considers consistent. Is it more
> > consistent to treat tuples as transparent and consider every component
> with
> > type `a`, or is it more consistent to treat tuples as opaque and reuse
> the
> > existing Foldable instance for tuples even if it might cause a compile
> time
> > error?
> >
> >
> > On Tue, Mar 21, 2017, 4:34 PM David Feuer <david.feuer at gmail.com> wrote:
> >>
> >> This seems much too weird:
> >>
> >> *> :set -XDeriveFoldable
> >> *> data Foo a = Foo ((a,a),a) deriving Foldable
> >> *> length ((1,1),1)
> >> 1
> >> *> length $ Foo ((1,1),1)
> >> 3
> >>
> >> I've opened Trac #13465 [*] for this. As I write there, I think the
> >> right thing is to refuse to derive Foldable for a type whose Foldable
> >> instance would currently fold over components of a tuple other than
> >> the last one.
> >>
> >> I could go either way on Traversable instances. One could argue that
> >> since all relevant components *must* be traversed, we should just go
> >> ahead and do that. Or one could argue that we should be consistent
> >> with Foldable and refuse to derive it.
> >>
> >> What do you all think?
> >>
> >> [*] https://ghc.haskell.org/trac/ghc/ticket/13465
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