GADTs and functional dependencies?

[Iavor Diatchki]

Hello Conal,

the implementation of fun-deps in GHC is quite limited, and they don't do
what you'd expect with existential types (like in your example),
type-signatures, or GADTs.   Basically, GHC only uses fun-deps to fill-in
types for unification variables, but it won't use them to reason about
quantified variables.

Here is an example that shows the problem, just using type signatures:

> class F a b | a -> b where
>   f :: a -> b -> ()
>
> instance F Bool Char where
>  f _ _ = ()
>
> test :: F Bool a => a -> Char
> test a = a

GHC rejects the declaration for `test` because there it needs to prove that
`a ~ Char`.  Using the theory of fun-deps, the equality follows because
from the fun-dep we know that:

forall x y z. (F x y, F x z) => (y ~ z)

Now, if we instantiate this axiom with `Bool`, `Char`, and `a`, we can
prove that `Char ~ a` by combining the instance and the local assumption
from the signature.

Unfortunately, this is exactly the kind of reasoning GHC does not do.   I
am not 100% sure on why not, but at present GHC will basically do all the
work to ensure that the fun-dep axiom for each class is valid (that's all
the checking that instances are consistent with their fun-deps), but then
it won't use that invariant when solving equalities.

I hope this helps!
-Iavor























On Tue, Mar 1, 2016 at 9:38 AM, Conal Elliott <conal at conal.net> wrote:

> Do GADTs and functional dependencies get along? I'm wondering why the
> following code doesn't type-check under GHC 7.10.3 and 8.1.20160224:
>
> > {-# OPTIONS_GHC -Wall #-}
> > {-# LANGUAGE GADTs, KindSignatures, MultiParamTypeClasses,
> FunctionalDependencies #-}
> >
> > module FundepGadt where
> >
> > class C a b | a -> b
> >
> > data G :: * -> * where
> >   -- ...
> >   GC :: C a b => G b -> G a
> >
> > instance Eq (G a) where
> >   -- ...
> >   GC b  == GC b' = b == b'
>
> Error message:
>
>     FundepGadt.hs:14:25: error:
>         • Couldn't match type 'b1’ with 'b’
>           'b1’ is a rigid type variable bound by
>             a pattern with constructor: GC :: forall a b. C a b => G b ->
> G a,
>             in an equation for '==’
>             at FundepGadt.hs:14:12
>           'b’ is a rigid type variable bound by
>             a pattern with constructor: GC :: forall a b. C a b => G b ->
> G a,
>             in an equation for '==’
>             at FundepGadt.hs:14:3
>           Expected type: G b
>             Actual type: G b1
>         • In the second argument of '(==)’, namely 'b'’
>           In the expression: b == b'
>           In an equation for '==’: (GC b) == (GC b') = b == b'
>         • Relevant bindings include
>             b' :: G b1 (bound at FundepGadt.hs:14:15)
>             b :: G b (bound at FundepGadt.hs:14:6)
>
> I think the functional dependency does ensure that "b == b" is well-typed.
>
> In contrast, the following type-family version does type-check:
>
> >     {-# OPTIONS_GHC -Wall #-}
> >     {-# LANGUAGE GADTs, KindSignatures, TypeFamilies #-}
> >
> >     module TyfamGadt where
> >
> >     class C a where
> >       type B a
> >
> >     data G :: * -> * where
> >       -- ...
> >       GC :: C a => G (B a) -> G a
> >
> >     instance Eq (G a) where
> >       -- ...
> >       GC b  == GC b' = b == b'
>
> Thanks, - Conal
>
> _______________________________________________
> ghc-tickets mailing list
> ghc-tickets at haskell.org
> http://mail.haskell.org/cgi-bin/mailman/listinfo/ghc-tickets
>
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://mail.haskell.org/pipermail/ghc-devs/attachments/20160301/ec66f8ac/attachment.html>