CallStack naming

[Joachim Breitner]

Hi,

Am Mittwoch, den 20.01.2016, 09:24 -0800 schrieb Eric Seidel:
> The problem is that I don't know how to implement
> `withFrozenCallStack`
> (included in the wiki) as a Haskell function if CallStacks aren't
> implicit parameters under-the-hood.

breaking it further down, the problem is not with `withFrozenCallStack`
per se, but rather with any code that wants to set the current
callstack, e.g. anything of the current form

  let ?callStack = ...
  in ..

How would that look with a magic nullary constraint "AppendsCallStack"?
It’d probably need a built-in function

setCallStack :: CallStack -> (AppendsCallStack => a) -> a

with which we can likely implement `withFrozenCallStack` again:

withFrozenCallStack :: AppendsCallStack => (AppendsCallStack => a) -> a
withFrozenCallStack do_this =
  -- we pop the stack before freezing it to remove
  -- withFrozenCallStack's call-site
  let callStack = freezeCallStack (popCallStack callStack)
  in setCallStack callStack do_this

It might need a second call to popCallStack depending on the precise
semantics of `callStack :: AppendsCallStack => CallStack` (i.e. whether
that does pop one entry off itself).

Greetings,
Joachim


-- 
Joachim “nomeata” Breitner
  mail at joachim-breitner.de • http://www.joachim-breitner.de/
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  Debian Developer: nomeata at debian.org

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