[Haskell-beginners] Function with mod cases?

[Lawrence Bottorff]

I'm looking through *An Introduction to Functional Programming Systems
Using Haskell *by Davie and one of the exercises is

*Define a function* f *such that*

f(x) = x + 3 (mod 5)

*Make a version that elaborates cases, as well as a straightforward way.*

I'm not really sure what's being asked, so this is what I've come up with

myMods xs = map (\x -> (x + 3) `mod` 5) xs

> myMods [1..20]
[4,0,1,2,3,4,0,1,2,3,4,0,1,2,3,4,0,1,2,3]

but when he says *make a version that elaborates cases *I'm not sure what
more there is to do.
What am I missing?

LB
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