[Haskell-beginners] '/' instead use 'DIV'. why?

[amindfv at gmail.com]

It might help to imagine if you flip your arguments:

length [23, 34, 45] / 6 :: Int

How do you represent 3/6 as an Int?

> El 17 abr 2020, a las 03:19, Alexander Chen <alexander at chenjia.nl> escribió:
> 
> Hi, 
> 
> 
> Prelude> :t (/)
> (/) :: Fractional a => a -> a -> a
> 
> Prelude> :t div
> div :: Integral a => a -> a -> a
> 
> 
> Prelude> 6 / length [23,34,45]
> error 
> 
> Prelude> 6 / 3
> 2.0
> 
> Could somebody explain to me why this is?
> 
> thanks,
> 
> Alexander Chen
> 
> 
> 
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