[Haskell-beginners] Bound library questions

[David McBride]

The code as it currently stands only has two nested fmaps / foldMaps /
traverses.

The reason he can do that is because Scope is defined as an "f (Var b a)".
Since Scope is only a functor if f is also functor, that means you can fmap
over f, regardless of what it is.  But in addition to that Var is also a
functor.  So you can fmap over f, and then fmap over the Var inside the f,
which ends up being two nested fmaps.  That same condition exists for
foldable and traversable.

On Fri, Aug 17, 2018 at 6:46 AM, Anthony Lee <anthonynlee at gmail.com> wrote:

> In Scope.hs there are some functions I feel difficult to understand,
> Why fmap/foldmap/traverse is applied three times?
>
> instance Functor f => Functor (Scope b f) where
> fmap f (Scope a) = Scope (fmap (fmap (fmap f)) a)
> {-# INLINE fmap #-}
>
> -- | @'toList'@ is provides a list (with duplicates) of the free variables
> instance Foldable f => Foldable (Scope b f) where
> foldMap f (Scope a) = foldMap (foldMap (foldMap f)) a
> {-# INLINE foldMap #-}
>
> instance Traversable f => Traversable (Scope b f) where
> traverse f (Scope a) = Scope <$> traverse (traverse (traverse f)) a
> {-# INLINE traverse #-}
>
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