[Haskell-beginners] runState (liftM (+100) pop) [1, 2, 3, 4] (Example from LYH)
fa-ml at ariis.it
Tue Oct 24 09:32:53 UTC 2017
On Tue, Oct 24, 2017 at 10:17:46AM +0100, Olumide wrote:
> ghci> runState (fmap (+100) pop) [1,2,3,4]
> Even though I'm still struggling to wrap my mind around monads, I sort of
> understand what's going on here. The problem is that I can't explain why the
> function (+100) is applied to _only_ the value 1 in (1,[2,3,4]).
if we look at the instance of `fmap` for State we'll find (more or
fmap :: (a -> b) -> State s a -> State s b
So fmap modifies the *result*, not the *state* itself.
If we also recall that `State s a` is nothing but `\s -> (a, s)` then
it is easy to see that only the first element of the tuple (the
so called result, `a`) will be modified.
Does this clear your doubts?
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