[Haskell-beginners] Why isn't :t (1+1) Integer

[Lai Boon Hui]

Hi,
i read that the default type for Num is Integer.
If we specify a type for one of the arguments:
:t (1 + 1::Double) is Double

If we don't, i expect the default type for Num to come into play:
However :t (1 + 1) is Num a => a

Why is that so?

-- 
Best Regards,
Boon Hui
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