[Haskell-beginners] pattern matching on a common element

[Rahul Muttineni]

data X =
  A1 { name :: String, d :: Double}
| A2 { name :: String, i :: Int}
| A3 { name :: String, d1 :: Double, i1 :: Int}

Now you can use `name` directly to get the string component of the
different variants.

Hope that helps!
Rahul

On Fri, Nov 25, 2016 at 11:16 AM, <briand at aracnet.com> wrote:

> Here's what I'm doing:
>
> data X = A1 String Double | A2 String Int | A3 String Double Int
>
> name c =
>   case c of
>     A1 name _ -> name
>     A2 name _ -> name
>     A3 name _ _ -> name
>
> I'm sure there's a better way...
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-- 
Rahul Muttineni
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