[Haskell-beginners] The (x:xs) in function parameter is a tuple?

[Nan Xiao]

Hi all,

Firstly, thanks very much for all responses!

Rein referred "A tuple can have any number of elements", while Graham
referred "There's no "one-ple", or 1-tuple, in Haskell.". So which one
is right? The tuple at least contains 2 elements?

Thanks very much in advance!
Best Regards
Nan Xiao


On Thu, Feb 25, 2016 at 2:37 AM, Graham Gill <math.simplex at gmail.com> wrote:
> Hi Nan, are you just confused about the use of the parentheses "(" and ")"?
>
> (x1,x2), (x1,x2,x3), ... are tuples in Haskell, but (x:xs) is not. (There's
> no "one-ple", or 1-tuple, in Haskell.) In
>
> occurs value [] = 0
> occurs value (x:xs) = (if value == x then 1 else 0) + occurs value xs
>
> the "(" and ")" around "x:xs" are just there for grouping, for operator
> precedence reasons. Function application binds more tightly than ":". If you
> leave the parentheses off, such as in
>
> occurs value x:xs = ...
>
> you'll get a parse error.
>
> Graham
>
>
>
> On 2/24/2016 5:31 AM, Nan Xiao wrote:
>>
>> Hi all,
>>
>> Greetings from me!
>>
>> I am confused about the function parameters and tuple. E.g.:
>>
>> occurs value [] = 0
>> occurs value (x:xs) = (if value == x then 1 else 0) + occurs value xs
>>
>> should we consider (x:xs) as a tuple?
>>
>> Thanks in advance!
>>
>> Best Regards
>> Nan Xiao
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