[Haskell-beginners] approximate string search
Sylvain Henry
sylvain at haskus.fr
Wed Apr 27 03:50:04 UTC 2016
Hi,
The ListLike instance for ByteString is defined here:
https://hackage.haskell.org/package/ListLike-3.1.7.1/docs/src/Data-ListLike-Instances.html
The implementation of Levenshtein distance in language-spelling is here:
https://hackage.haskell.org/package/language-spelling-0.3.2/docs/src/Language-Distance.html#levenshtein
It seems to use only O(1) operations on the Bytestring: length and index
(!!).
It uses an unboxed mutable vector in the ST monad.
It is specialized for ByteString.
So I think it should be quite efficient already. If you want you can use
the same approach to implement the other algorithm, with Data.Bits for
the bit-fiddling:
https://hackage.haskell.org/package/base-4.8.2.0/docs/Data-Bits.html
Cheers,
Sylvain
On 27/04/2016 01:17, Mason Lai wrote:
> Hi,
>
> I'm writing a Haskell program which is looking for whether or not a
> string (needle) exists within a larger string (haystack) given a
> Levenshtein distance. Note that it shouldn't calculate the Levenshtein
> distance between the needle and haystack. For example,
>
> needle: AAA
> haystack: TTTTTAATTTTT
>
> The needle would be "found" if the Levenshtein distance is set at 1,
> because dist("AAT", "AAA") == 1.
>
> The following almost works:
>
> distance(needle, haystack) - (len(haystack) - len(needle))
>
> But it does not handle deletions correctly.
>
> I've previously written a program which does this approximate search
> in Java with the Wu-Manber extension of the Bitap, or shift-or,
> algorithm. The same strategy seems difficult to code up in Haskell
> because it's very "stateful" and involves a lot of bit-fiddling.
> (Maybe it's actually quite simple, but I'm not sure how I would go
> about doing this.)
>
> As a further complication, I'd prefer to keep the data packed as
> ByteStrings, as I'll be dealing with around 200 GiBs of data (split
> and parallelized over a cluster, but still a lot). I don't really know
> how to deal with ByteStrings without using the functions that come
> along in the ByteString module or unpacking the ByteString.
>
> I've been using the language-spelling package, which has a module
> which can calculate the Levenshtein distance between two ByteStrings.
> I see that it uses ListLike. I'm not really sure how it works, but I
> assume it makes ByteString an instance of ListLike, and then you have
> access to all of the ListLike methods?
>
> Does anyone have any advice on how I should proceed with this? I don't
> mind learning new things, but I don't really know what the best
> strategy is or where to look.
>
> -- Mason
>
>
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