[Haskell-beginners] Couldn't match expected type `(a0 -> [a0]) -> [a0]', with actual type `[a0]'
Roelof Wobben
r.wobben at home.nl
Sat May 23 06:58:50 UTC 2015
Hello,
For some reasons my file's are corrupted.
I had repair them with success except this one.
Here is the code :
toDigits number
| number <= 0 = []
| otherwise = toDigits' [] number
where
toDigits' acc 0 = acc
toDigits' acc number = ((number `mod` 10 ): acc) (toDigits'
(number `mod` 10))
main = print $ toDigits 123
and here is the error:
Couldn't match expected type `(a0 -> [a0]) -> [a0]'
with actual type `[a0]'
The function `(number `mod` 10) : acc' is applied to one argument,
but its type `[a0]' has none
In the expression:
((number `mod` 10) : acc) (toDigits' (number `mod` 10))
In an equation for toDigits':
toDigits' acc number
= ((number `mod` 10) : acc) (toDigits' (number `mod` 10))
Roelof
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