[Haskell-beginners] oddsFrom3 function

akash g akaberto at gmail.com
Mon Aug 17 08:46:10 UTC 2015


You can also peruse SICP for knowing about how lazy evaluation works.  The
explanations are nice.  It is in lisp, though.

https://mitpress.mit.edu/sicp/full-text/book/book-Z-H-24.html#%_sec_3.5

On Mon, Aug 17, 2015 at 2:12 PM, akash g <akaberto at gmail.com> wrote:

> Hi Rein,
>
> The initial version which the OP posted doesn't have a terminal value.
> The OP had posted the version that he'd wanted clarification on.
>
> On Mon, Aug 17, 2015 at 12:40 PM, Rein Henrichs <rein.henrichs at gmail.com>
> wrote:
>
>> It will absolutely work. Lists can be infinite in Haskell and infinite
>> lists are productive:
>>
>> λ> take 5 oddsFrom3
>> [3,5,7,9,11]
>>
>>
>> On Mon, Aug 17, 2015 at 12:05 AM Debdut Karmakar <debdutk at gnulinuxed.tk>
>> wrote:
>>
>>> On 2015-08-17 02:35, akash g wrote:
>>>
>>> Not a problem.  And I should have thought about what you wanted too.
>>>
>>> This version will give you an infinite list of odd numbers from 3.
>>>
>>>
>>> On Mon, Aug 17, 2015 at 12:02 PM, Debdut Karmakar <debdutk at gnulinuxed.tk
>>> > wrote:
>>>
>>>> Sorry, I wrote a wrong function, the correct version is:
>>>>
>>>> oddsFrom3 :: [Integer]
>>>> oddsFrom3 = 3 : map (+2) oddsFrom3
>>>> --
>>>>
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>>>
>>> I know that it will evaluate to a list of odd numbers >= 3, but how?
>>>
>>> Thanks, anyway.
>>> --
>>>
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