[Haskell-beginners] Instance declaration needs more info?
Dimitri DeFigueiredo
defigueiredo at ucdavis.edu
Wed May 21 16:51:24 UTC 2014
Got it. I was mistaken in what the final "Unit c =>" meant. Thanks Bob!
Em 21/05/14 03:28, Bob Ippolito escreveu:
> The trouble is that your specification says that Unit c is the return
> type (the caller can choose any Unit instance), but this
> implementation can only evaluate to a Prelude.Double. One way to solve
> this is to add a fromDouble :: Double -> Unit a and wrap the
> expression with that in order to satisfy Unit c.
>
> On Wednesday, May 21, 2014, Dimitri DeFigueiredo
> <defigueiredo at ucdavis.edu <mailto:defigueiredo at ucdavis.edu>> wrote:
>
> Hi All,
>
> I'm trying to write a simplified dimensional library where where
> quantities in meters, seconds and meters/second can all co-exist
> adjusting their respective units when multiplied and/or divided.
>
> Also, meter+meter is allowed, but meter+second should cause the
> type checker to complain.
>
> This is a bit like a *much* simplified version of the Units
> library. However, I am having trouble understanding why my
> instance declaration below appears to be under specified. Here's
> the code:
>
> ------------
> module Dimensional where
> import qualified Prelude
>
> -- A Group allows you to add and subtract (but not multiply or divide)
> class Group a where
>
> (+) :: a -> a -> a
>
> (-) :: a -> a -> a
> x - y = x + negate y
>
> negate :: a -> a
> negate x = fromInteger 0 - x
>
> fromInteger :: Prelude.Integer -> a
>
> class Unit a where
>
> (*) :: (Unit a, Unit b, Unit c) => a -> b -> c
> (/) :: (Unit a, Unit b, Unit c) => a -> b -> c
> toDouble :: a -> Prelude.Double
>
> instance Unit Prelude.Double where
>
> (*) x y = (Prelude.*) x (toDouble y) -- <----- Error here
> (/) x y = (Prelude./) x (toDouble y)
> toDouble x = x
>
> ------------
> GHC complains as follows:
>
> Could not deduce (c ~ Prelude.Double)
> from the context (Unit Prelude.Double, Unit b, Unit c)
> bound by the type signature for
> * :: (Unit Prelude.Double, Unit b, Unit c) =>
> Prelude.Double -> b -> c
> at /code/haskell/dimensional.hs:25:5-43
> `c' is a rigid type variable bound by
> the type signature for
> * :: (Unit Prelude.Double, Unit b, Unit c) =>
> Prelude.Double -> b -> c
> at /code/haskell/dimensional.hs:25:5
> In the first argument of `(Prelude.*)', namely `x'
> In the expression: (Prelude.*) x (toDouble y)
> In an equation for `*': * x y = (Prelude.*) x (toDouble y)
>
> Any pointers would be much appreciated!
>
> Thanks,
>
> Dimitri
>
>
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