[Haskell-beginners] Error Message when trying to solve alphametic(SEND + MORE = MONEY)
Matthew Moppett
matthewmoppett at gmail.com
Sun Jan 26 12:31:19 UTC 2014
Sorry about the last post -- I accidentally clicked "send" before I'd
written my message.
Sok Ha:
expr = show send ++ "+" ++ show more ++ "=" show money
should read
expr = show send ++ "+" ++ show more ++ "=" ++ show money
The error message is rather cryptic -- ghc seems to assume that "=" must be
intended as a function, since it it has other values (potential arguments)
to the right of it. I usually don't spend much time trying to figure out
ghc error messages unless I really can't solve the problem by just looking
over the offending line carefully. Very often it's just a typo (as it seems
to be in your case).
On Sun, Jan 26, 2014 at 7:24 PM, Matthew Moppett
<matthewmoppett at gmail.com>wrote:
> Hi Sok Ha.
>
> expr = show send ++ "+" ++ show more ++ "=" show money
>
>
>
> On Sun, Jan 26, 2014 at 7:16 PM, Sok Ha Chang <shaegis at gmail.com> wrote:
> > Hi.
> > I’m new to Haskell.
> > Use Haskell Platform on MacBook Air.
> > $ ghc --version
> > The Glorious Glasgow Haskell Compilation System, version 7.6.3
> >
> > I’m try to solve alphametic.
> > SEND + MORE = MONEY
> >
> > Here is code…
> >
> ----------------------------------------------------------------------------------------------------------
> > import Data.List
> >
> > decryp :: [Int] -> String -> String
> > decryp (s:e:n:d:o:r:y:[]) a =
> > if send + more == money then expr:a else a
> > where
> > send = s * 1000 + e * 100 + n * 10 + d
> > more = 1000 + o * 100 + r * 10 + e
> > money = 10000 + o * 1000 + n * 100 + e * 10 + y
> > expr = show send ++ "+" ++ show more ++ "=" show money
> >
> > decrypSolver :: [String]
> > decrypSolver =
> > foldr decryp [] (permutations 7 [0, 2, 3, 4, 5, 6, 7, 8, 9])
> >
> ----------------------------------------------------------------------------------------------------------
> >
> > Error Messages is
> > ./decrypSolver.hs: line 10, column 60:
> > Couldn't match expected type `(a0 -> String) -> Int -> [Char]'
> > with actual type `[Char]'
> > The function `"="' is applied to two arguments,
> > but its type `[Char]' has none
> > In the second argument of `(++)', namely `"=" show money'
> > In the second argument of `(++)', namely
> > `show more ++ "=" show money’
> >
> ----------------------------------------------------------------------------------------------------------
> >
> > How can I fix this?
> >
> > Thank you.
> >
> > Sincerely, S. Chang
> > _______________________________________________
> > Beginners mailing list
> > Beginners at haskell.org
> > http://www.haskell.org/mailman/listinfo/beginners
>
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