[Haskell-beginners] Picking apart getLine
anguscomber at gmail.com
Tue Jan 7 17:38:19 UTC 2014
OK, so if the user enters "ABC\n" then the following happens:
x <- getChar --A
x <- getChar --B
x <- getChar --B
x <- getChar --\n
levels are different contexts? levels of recursion.
then when recursion ends get 'A' : 'B' : 'C' : 
So does the (x:xs) syntax mean this?
I thought of (x:xs) as 'A' : ['B','C'] But can the xs mean simply the
rest? ie (x:xs) in this case x = 'A' and xs represents the rest 'B' : 'C'
:  Is that maybe the way to think of it?
I suppose it does.
The confusing bit is how all the x's after the first one (ie after 'A') are
represented in returm (x:xs). But I am now thinking that ['B','C'] is
actually the same as 'B' : 'C' :  and all that the 'B' and 'C' and also
the last  are the xs part of (x:xs)
On 7 January 2014 17:15, David McBride <toad3k at gmail.com> wrote:
> You have the idea. The x is fetched with getChar, then it sits in
> that context until the return is executed.
> So the x is sitting there and getLine' is called. It makes its own x
> via getChar, then maybe getLine' is called again. Each getLine' sits
> there with its own version of x until finally the last getLine' get's
> a \n, and then returns a . Then the whole thing unwinds by
> prepending x to , then x to [x], then another x to [x,x], until
> there are no more x's to return, and you have the whole string.
> Hopefully that paragraph makes sense.
> On Tue, Jan 7, 2014 at 11:54 AM, Angus Comber <anguscomber at gmail.com>
> > Before looking at getLine, I can understand this:
> > getnumber :: IO Int
> > getnumber = do x <- getChar
> > if isDigit x then
> > return (ord x - ord '0')
> > else
> > return 0
> > OK, it is not a very useful function but at least I understand it.
> > is required so that the function returns an IO Int.
> > But I don't understand this:
> > getLine' :: IO String
> > getLine' = do x <- getChar
> > if x == '\n' then
> > return 
> > else
> > do
> > xs <- getLine'
> > return (x:xs)
> > I can understand what will happen if a user enters a newline (only).
> >  brings the empty list into the monadic world.
> > But what is happening if x is not a newline?
> > xs <- getLine' will recursively call getChar and retrieve another
> > from the input stream. But it will do this BEFORE the return (x:xs) - so
> > what is happening to all the head elements in the list - the x element?
> > It is difficult to picture in my mind how this is working. I understand
> > recursion but this looks tricky.
> > Can someone help me work this out?
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