[Haskell-beginners] Given a list of lists, how to drop the last item in each (sub)list.
akaberto at gmail.com
Thu Jan 2 12:02:42 UTC 2014
You map the drop function over the list.
Something like this will do
foo xs = map (take 8) xs
On Thu, Jan 2, 2014 at 5:08 PM, Angus Comber <anguscomber at gmail.com> wrote:
> I have a list like this:
> The 'inner' list is a list of 9 items. I want to process the list so that
> a list of lists is returned but the 9th element in each inner list is
> So the function type would be [[a]] -> [[a]]
> So to get started I wrote a function like this:
> discardparitybyte :: [[Bit]] -> [[Bit]]
> But then not sure how to transform the inner list.
> I know I can access the first inner element using take 1 list. But how do
> I then access/manipulate this inner list?
> discardparitybyte (x:xs) = take 9 ??? (take 1 xs) : discardparitybyte ???
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