[Haskell-beginners] Question on evaluating function compostion

[Erik Price]

>
> Why did Haskell, however, not try to fully evaluate addition,
> like following?
> (liftM . (+)) 1 [2]   --->
>   liftM ((+) 1 [2])   --->
>   error
>

Haskell functions only consume one argument, not two. The composed function
is applied to the first argument, which is 1. That returns a new function,
which is applied to the next argument, which is [2].

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